27 miles per gallon into kilometers per liter.

Answers

Answer 1

Answer:

11.479 kilometres per litre

Explanation:

for an approximate result, divide the fuel economy value by 2.352

Answer 2

27 miles per gallon is equivalent to approximately 6.09 kilometers per liter.

What is Unit conversion?

A statement of the connection between units that are used to alter the units of a measured quantity without affecting the value is called a conversion factor. A conversion ratio (or unit factor), if the numerator and denominator have the same value represented in various units, always equals one (1).

To convert 27 miles per gallon to kilometers per liter, we need to use conversion factors:

1 mile = 1.60934 kilometers

1 gallon = 3.78541 liters

So, first we convert miles to kilometers:

27 miles * 1.60934 km/mile = 43.45218 kilometers

Then we convert gallons to liters:

1 gallon = 3.78541 liters

27 miles per gallon = 27 miles / 1 gallon = 27 / 3.78541 liters/mile = 7.13888 liters/kilometer

Finally, we divide the distance traveled in kilometers by the amount of fuel used in liters:

43.45218 km / 7.13888 liters = 6.09023 kilometers per liter

Therefore, 27 miles per gallon is equivalent to approximately 6.09 kilometers per liter.

Learn more about unit conversion here:

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Related Questions

a current of 5 ampere is passed for 2 hours in an electric iron having a resistance of 100 ohms calculate the heat produced

Answers

Answer:

[tex] \boxed{\sf Heat \ produced \ (H) = 5 \ kWh} [/tex]

Given:

Resistance (R) = 100 Ω

Current (I) = 5 A

Time (t) = 2 hours

To Find:

Heat developed (H) in the electric iron

Explanation:

Formula:

[tex] \boxed{ \bold{ \sf H = I^2Rt}}[/tex]

Substituting values of I, R & t in the equation:

[tex] \sf \implies H = {5}^{2} \times 100 \times 2 \\ \\ \sf \implies H = 25 \times 100 \times 2 \\ \\ \sf \implies H = 5000 \\ \\ \sf \implies H = 5 \: kWh [/tex]

[tex] \therefore[/tex]

Heat developed (H) in the electric iron = 15 kWh

What happens when sulfur reacts with potassium?

Answers

Electrons move from the potassium atoms to the sulfur atoms.

A 20 kg block rests on a rough horizontal table. A rope is attatched to the block and is pulled with a force of 80 N to the left. As a result, the block accelerates at 2.5 m/s^2 . The coefficient is Kinetic force friction between the block and the table is ____( Round to the nearest hundredth )

Answers

Given :

Mass of block , M = 20 kg .

Force applied , F = 80 N .

Acceleration of block , [tex]a=2.5\ m/s^2[/tex] .

To Find :

The coefficient is Kinetic force friction between the block and the table .

Solution :

We know , Force equation on block is given by :

[tex]F_{net }=F-\mu_k mg \\\\ma = F-\mu_k mg \\\\20\times 2.5 = 80 -\mu_k \times 20 \times 10\\\\\mu_k\times 200=30\\\\\mu_k=\dfrac{30}{200}\\\\\ mu_k=0.15[/tex]

Therefore , coefficient is Kinetic force friction between the block and the table is 0.15 .

Hence , this is the required solution .

True or false: We still use the republican calendar created by the French.​

Answers

true!!!!!!!!!!!!!!!!!!!!

Convert 543 g to kg (Use correct number of significant figures for answer).
a
Ob
e
0.5 kg
0.54 kg
0.543 kg
5.0 kg
5.4 kg
5.43 kg
54,300 kg
543,000 kg
None are Correct
g

Answers

Answer:

0.543 kilogram

Explanation:

thats the answer

A roadrunner at rest suddenly spots a rattlesnake slithering directly away at a constant speed of 0.75 m/s. At the moment the snake is 10. Meters from the bird, the roadrunner starts chasing it with a constant acceleration of 1.0 m/s^2. How long will it take the roadrunner to catch up to the snake?

Answers

Answer:

The roadrunner will take approximately 5.285 seconds to catch up to the rattlesnake.

Explanation:

From the statement we notice that:

1) Rattlesnake moves a constant speed ([tex]v_{S} = 0.75\,\frac{m}{s}[/tex]), whereas the roadrunner accelerates uniformly from rest. ([tex]v_{o, R} = 0\,\frac{m}{s}[/tex], [tex]a = 1\,\frac{m}{s^{2}}[/tex])

2) Initial distance between the roadrunner and rattlesnake is 10 meters. ([tex]x_{o, R} = 0\,m[/tex], [tex]x_{o,S} = 10\,m[/tex])

3) The roadrunner catches up to the snake at the end. ([tex]x_{S} = x_{R}[/tex])

Now we construct kinematic expression for each animal:

Rattlesnake

[tex]x_{S} = x_{o,S}+v_{S}\cdot t[/tex]

Where:

[tex]x_{o, S}[/tex] - Initial position of the rattlesnake, measured in meters.

[tex]x_{S}[/tex] - Final position of the rattlesnake, measured in meters.

[tex]v_{S}[/tex] - Speed of the rattlesnake, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

Roadrunner

[tex]x_{R} = x_{o,R} +v_{o,R}\cdot t +\frac{1}{2}\cdot a\cdot t^{2}[/tex]

Where:

[tex]x_{o, R}[/tex] - Initial position of the roadrunner, measured in meters.

[tex]x_{R}[/tex] - Final position of the roadrunner, measured in meters.

[tex]v_{o,R}[/tex] - Initial speed of the roadrunner, measured in meters per second.

[tex]a[/tex] - Acceleration of the roadrunner, measured in meters per square second.

[tex]t[/tex] - Time, measured in seconds.

By eliminating the final positions of both creatures, we get the resulting quadratic function:

[tex]x_{o,S}+v_{S}\cdot t = x_{o,R}+v_{o,R}\cdot t +\frac{1}{2}\cdot a \cdot t^{2}[/tex]

[tex]\frac{1}{2}\cdot a \cdot t^{2} + (v_{o,R}-v_{S})\cdot t + (x_{o,R}-x_{o,S}) = 0[/tex]

If we know that [tex]a = 1\,\frac{m}{s^{2}}[/tex], [tex]v_{o, R} = 0\,\frac{m}{s}[/tex], [tex]v_{S} = 0.75\,\frac{m}{s}[/tex], [tex]x_{o, R} = 0\,m[/tex] and [tex]x_{o,S} = 10\,m[/tex], the resulting expression is:

[tex]0.5\cdot t^{2}-0.75\cdot t -10=0[/tex]

We can find its root via Quadratic Formula:

[tex]t_{1,2} = \frac{-(-0.75)\pm \sqrt{(-0.75)^{2}-4\cdot (0.5)\cdot (-10)}}{2\cdot (0.5)}[/tex]

[tex]t_{1,2} = \frac{3}{4}\pm \frac{\sqrt{329}}{4}[/tex]

Roots are [tex]t_{1} \approx 5.285\,s[/tex] and [tex]t_{2}\approx -3.785\,s[/tex], respectively. Both are valid mathematically, but only the first one is valid physically. Hence, the roadrunner will take approximately 5.285 seconds to catch up to the rattlesnake.

When exercising, which hormone level decreases in females often causing a better mood?
Estrogen
Adrenaline
Blood Sugar
Cortisol

Answers

Answer:

The correct option is;

Adrenalin

Explanation:

The presence of Adrenalin can cause headaches, memory loss, confusion, make a person unable to concentrate, and therefore, generally affects the mode in female, as such it is important for a decrease the level of Adrenalin by exercising, which causes the Adrenalin and cortisol to reduce in a similar  way to consuming gasoline by burning gasoline, cardiovascular exercises burns Adrenaline.

Doing exercises causes adrenaline and cortisol, which are the body's stress hormones to be reduced.

Answer:

It's adrenaline

Explanation:

I just took a quiz and got it right

find the potential energy of a diver of mass 75kg at a height of 10m above a swimming pool g=9.8m

Answers

Answer:

[tex] \boxed{\sf Potential \ energy \ (PE) = 7.35 \ kJ} [/tex]

Given:

Mass (m) = 75 kg

Height (h) = 10 m

Acceleration due to gravity (g) = 9.8 m/s²

To Find:

Potential Energy (PE)

Explanation:

The formula for potential energy due to gravity:

[tex] \boxed{ \bold{PE = mgh}}[/tex]

Substituting value of m, g & h in the formula:

[tex] \sf \implies PE = 75 \times 10 \times 9.8 \\ \\ \sf \implies PE = 7350 \: J \\ \\ \sf \implies PE = 7.35 \: kJ[/tex]

Plz help me this question is hard to under stand

Answers

Answer:

____________

in real world conditions?

it seems the most plausible.

Answer (B)

Cars are tested on closed tracks and race tracks so rule out A, D. Tha leaves us with B, C. C is kind of a real-world situation so the answer is most likely, B.

A long, nonconducting, solid cylinder of radius 4.0 cm has a nonuniform volume charge density r that is a function of radial distance r from the cylinder axis: r ! Ar2 . For A ! 2.5 mC/m5 , what is the magnitude of the electric field at (a) r ! 3.0 cm and (b) r ! 5.0 cm?

Answers

Answer:

a) 1.91 c/m

b) 3.62 c/m

Explanation:

See attached image

What are 3 macro nutrients

Answers

Answer:

proteins carbohydrates and fats

Explanation:

Answer:

Carbohydrates, Proteins, and Fats.

1 point
In a biology experiment the number of yeast cells is determined after 24
hours of growth at different temperatures. What is the INDEPENDENT
variable? *
type of yeast
24 hour time period
different temperatures
number of yeast cells

Answers

Answer:

different temperatures

Explanation:

The independent variable would be different temperatures.

The independent variable is the variable that is manipulated or varied in an experiment in order to see the effects it will produce on another variable - the dependent variable. The values of the independent variable are directly inputted by the researcher and are not changed by any other variable throughout the experiment.

In the illustration, the effect of a variation in temperature is determined by counting the number of yeast cells. This showed that the manipulated variable is the temperature and hence, the independent variable.

Tell me about your experiences with science​

Answers

Answer:

Well i once did an expiremnet and it exploaded in my face lol

Explanation:

Answer:

so good

Explanation:

perfect nice and explody too much

What is the difference between centrifugal force and centripetal force???

Answers

Centripetal force is defined as, "the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation," while centrifugal force is defined as "the apparent force that is felt by an object moving in a curved path that acts outwardly away from the center of rotation," according to Merriam Webster Dictionary.

Answer:

Centripetal force is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation, while centrifugal force is the apparent force that is felt by an object moving in a curved path that acts outwardly away from the center of rotation

Explanation:

Hope this helps!

Brainliest if correct pls

How many significant figures does the value 0.080 have?

Answers

The answer is 2 sig figs

2. Find the velocity when the displacement is 40 m and the time is 5 s.

Answers

Answer:

V=?

S= 40m

t=5s

V=S/t

V=40/5

V=8m/s

how many grams is 1dg?​

Answers

Answer:

Oh, I didn't know if u meant decigram or decagram! So for decagram there would be 10 grams and deci gram is 0.1 grams.  Hope this helps!!

Explanation:

Answer:

Hey there!

There are 10 grams in one decagram.

Let me know if this helps :)

2. What is the difference between distance and displacement?

Answers

Answer:

Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

Explanation:

:)

Answer: The complete length of the path between any two points is called distance. Displacement is the direct length between any two points when measured along the minimum path between them.

Explanation: It's what's!!

Plz help me I will mark brainlieat Ques. Write down name and molecular formula of a
Compound which gives hydrogen ion and sulphate on
in solution state. In which colour is the methyl Orange
changed after treating with this compound? Why?
Write name of salt when the same compound is
treated with sodium hydroxide Write down chemical
equation​

Answers

The compound is (Sulphuric Acid) H2SO4. On reacting with (Sodium Hydroxide) NaOH, it gives (2 Water Molecules/Colored) 2H2O and (1 Sodium Sulfate Molecule/Salt) Na2SO4

H2SO4 + NaOH —> 2H2O (aq.) + Na2SO4 (salt)

The resulted salt/compound (Na2SO4) when reacting with Methyl Orange (MO) is called ”Removal of methyl orange dye and Na2SO4 salt from synthetic wastewater using reverse osmosis (RO)”

The efficiency of reverse osmosis (RO) membranes used for treatment of colored water effluents can be affected by the presence of both salt and dyes.

Concentration polarization of each of the dye and the salt and the possibility of a dynamic membrane formed by the concentrated dye can affect the performance of the RO membrane.

The objective of the current work was to study the effect of varying the Na2SO4 salt and methyl orange (MO) dye concentrations on the performance of a spiral wound polyamide membrane.

The work also involved the development of a theoretical model based on the solution diffusion (SD) mass transport theory that takes into consideration a pressure dependent dynamic membrane resistance as well as both salt and dye concentration polarizations.

Control tests were performed using distilled water, dye/water and salt/water feeds to determine the parameters for the model.

The experimental results showed that increasing the dye concentration from 500 to 1000 ppm resulted in a decrease in the salt rejection at all of the operating pressures and for both feed salt concentrations of 5000 and 10,000 ppm.

Increasing the salt concentration from 5000 to 10,000 ppm resulted in a slight decrease in the percent dye removal. The model’s results agreed well with these general trends.

a car starts from rest and drives at 45 m/s in 20 s. how far did it travel

Answers

Answer:

distance=speed×time.

45×20=900m.

Which form of emission is commonly not written in nuclear equations because they do not affect charges, atomic numbers, or mass numbers?

Answers

Answer:

Gamma radiation .

Explanation:

Three types of emission result at the time of nuclear emission .

alpha emission

Beta emission

Gamma radiation emission

Gamma radiation results in the emission of gamma ray . This is a very high frequency radiation . It is not a particle having charge and mass like alpha and beta emission . So it has no effect on the mass and charge of the product that is formed after gamma radiation . The only effect it has on the product is that it reduces the kinetic energy of the emitting particles or it reduces the internal energy of the product . It causes negligible change in the mass of the product and no change in the charge of the product.

That is why , generally this product is not written in the nuclear reaction .

Answer:

The answer is Gamma ray

Explanation:

Because this is a very high frequency radiation, is not a particle having charge and mass like alpha and beta emission, so it has no effect on the mass and charge of the product that is formed after gamma radiation. The only effect it has on the product is that it reduces the kinetic energy of the emitting particles or it reduces the internal energy of the product, it causes negligible change in the mass of the product and no change in the charge of the product.

A charge +Q is located at the origin and a second charge, +4Q, is at distance d on the x-axis. If a third charge, q, is placed somewhere, so that all three charges will be in equilibrium.1. What should be its sign, so that all three charges will be in equilibrium?A. Negative.B. Positive.2. What should be its magnitude, so that all three charges will be in equilibrium?

Answers

Answer:

Third charge should be placed at a distance d/3

Sign is negative

Magnitude is |q| = 4Q/3

Explanation:

To find a place where a third charge, q, is placed so that all three charges will be in equilibrium would be at;

E1 = E2

Now, let the distance between the charges +Q and +4Q be d. Also, let the distance from charge +Q to the third charge q be x.

Thus;

E1 = kQ/x²

E2 = k(4Q)/(d - x)²

Since equilibrium, then;

E1 = E2 gives;

kQ/x² = k(4Q)/(d - x)²

k and Q will cancel out to give;

1/x² = 4/(d - x)²

Cross multiply to get;

(d - x)² = 4x²

Taking square root of both sides gives;

√(d - x)² = √4x²

Gives;

d - x = 2x

d = x + 2x

d = 3x

x = d/3

This is the point at which E1 = E2.

Since at equilibrium, it means that Fq + F2 = 0

Now, electric force formula is;

F = kq1*q2/r²

So; Fq = kqQ/x²

F2 = kQ(4Q)/d²

Equating Fq + F2 = 0 gives;

kqQ/x² + kQ(4Q)/d² = 0

kqQ/x² = -kQ(4Q)/d²

Like terms cancel out to get;

q/x² = -4Q/d²

q = - 4Qx²/d²

earlier we saw that x = d/3.

So, q = -4Q × (d/3)²/d²

q = -4Q × ⅓

q = - 4Q/3

Thus,it's sign is negative.

It's magnitude will be the positive value.

Thus, magnitude is;

|q| = 4Q/3

1). The sign that will be of all the given three charges being in equilibrium would be:

A). Negative

2). The magnitude to allow all the given three charges to remain in equilibrium would be:

- Magnitude [tex]|q| = 4Q/3[/tex]

Given that,

First Charge [tex]= +Q[/tex]

Second Charge[tex]= +4Q[/tex]

Third Charge [tex]= q[/tex]

The location where they will be in equilibrium would be:

[tex]E1 = E2[/tex]

So,

We will assume the distance between the first two charges i.e. +Q and +4Q as d and assume the distance from charge +Q to the third charge q as x.

Now,

[tex]E1 = kQ/x^2[/tex]

[tex]E2 = k(4Q)/(d - x)^2[/tex]

Therefore,

The equilibrium will be at:

[tex]kQ/x^2 = k(4Q)/(d - x)^2[/tex]

by solving we get,

[tex]x = d/3[/tex]

Because at equilibrium [tex]Fq + F2 = 0[/tex],

So,

F [tex]= kq1*q2/r^2[/tex]

and [tex]Fq = kqQ/x^2[/tex]

[tex]F2 = kQ(4Q)/d^2[/tex]

by resolving the equation, we get;

[tex]Fq + F2 = 0[/tex]

[tex]kqQ/x^2 + kQ(4Q)/d^2 = 0[/tex]

By solving it, we get

[tex]Magnitude(q) = - 4Q/3[/tex]

Thus, the sign is negative.  

and Magnitude |q| = 4Q/3

Thus, options A and [tex]|q| = 4Q/3[/tex] would be the correct answer.

Learn more about "Charge" here:

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write down formula of power​

Answers

There u go -> P=f/a

Answer:

Power is a measure of the amount of work that can be done in a given amount of time. So, the formula is the energy or work divided by time:

P = W ÷ T, where p is power , w is work and t is time.

The net external force on the propeller of a 3.32 kg model airplane is 23 N forward. What is the acceleration of the airplane?

Answers

Answer:

6.93 m/s^2

Explanation:

Given that the The net external force on the propeller of a 3.32 kg model airplane is 23 N forward

Where

Mass M = 3.32kg

Force F = 23 N

Force = mass × acceleration

Substitute all the parameters into the formula

23 = 3.32 × a

a = 23/3.32

a = 6.93 m/s^2

Therefore, the acceleration of the airplane is 6.93 m/s^2

Which of the following is an example of an electromagnetic wave? (2 points)

Red light

Ocean waves

Sound waves

Earthquakes

Answers

a) red light
red lights are an example of an electromagnetic wave. visible lights are the only electromagnetic waves we can actually see on the spectrum. red, in particular has the biggest wavelength.

b) ocean waves
ocean waves are not an electromagnetic wave. in fact, it’s a mechanical wave. electromagnetic waves can travel through a vacuum, that is empty space, but mechanical waves cannot.

c) sound waves
sound waves are also not an electromagnetic wave. it’s a mechanical wave. you cannot hear electromagnetic waves.

d) earthquakes
an earthquake is also not an example of electromagnetic waves. it’s a mechanical wave.

hope this helps!

Answer:

a

Explanation:

A race car speeds up with an acceleration of 10 m/s2 for 21 s. If its final velocity is 210 m/s, find its initial velocity.

Answers

Answer:

answer is 0m/ sec

please follow me.

This means divide or to take apart the pieces. ( science )

Answers

Answer:

disassemble, break apart,divide, separate

Explanation:

just know and have learned it....

In a college of exactly 2560 students, exactly 50 % are male. What is the number of female students?

Answers

1280- 50% of 2560 is 1280

Identify the term used to describe the number of protons and neutrons that are present in an atomic
nucleus.

Answers

Answer:
Atomic mass
Explanation:
The unit for measuring protons and neutrons are called atomic mass. They weigh around the same thing.
atomic number. explanation: the atomic number or proton number of a chemical element is the number of protons found in the nucleus of every atom of that element.

I want to know if high school starts hard and gets easier as the year goes? in your opinion

Answers

Answer:

It depends on how much you stress I recommend starting calm!

Explanation:

Answer:

I'm a senior right now, but I think the subjects gradually get more difficult, it's not all too difficult though, it's just stressful because the amount of work your expected to finish.

Explanation:

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