11. A ball rolls across a table of height 1.2 meters, leaves the table with a speed of ve, and lands 0.69m
from the edge of the table.
vo
1.2 m
-0.69 m
a. Find the time it takes the ball to fall from the edge of the table and reach position A in the picture
above.

Answers

Answer 1

Answer:

sorry don't know i just need points

Explanation:


Related Questions

which force is a contact force

Answers

contact forces include push, pull and friction

please help .-. its for physics

Answers

Answer:

your answer is correct

among 1 litre boiling water and red hot glowing nail which one has more amount of heat and why​

Answers

Answer: The Water

Explanation:

The boiling litre of water has more volume and so has more heated molecules per cubic metre so it will have a higher amount of heat than the glowing nail.

To practically test this, put the glowing nail into a litre of cold water and record the final temperature when the nail has cooled down. Repeat this with the boiling litre of water. You will notice a higher final temperature with the boiling water indicating that it had more heat.

answer them all please!!

Answers

Answer:

1. stomach

2. arteries

3. trachea

4. spinal cord

What are four pieces of evidence for continental drift?

Answers

continents, paleoclimate indicators, truncated geologic features, and fossils:D
They based their idea of continental drift on several lines of evidence: fit of the continents, paleoclimate indicators, truncated geologic features, and fossils.

1. A plane flying horizontally at an altitude of 490 meters and having a velocity of 250 meters per second east, drops a supply packet to a work crew on the ground. It falls freely without a parachute. [Assume no wind and negligible air resistance.] A. Calculate the time required for the packet to hit the ground. (25 pts)

Answers

Answer:

t = 10 s

Explanation:

Given :

Altitude, h = 490 m

Initial velocity of a plane, u = 250 m/s

To find :

The time required for the packet to hit the ground. When it hits the ground its velocity will be 0. Let t is the required time. It can be calculated as follows :

[tex]t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 490}{9.8}} \\\\t=10\ s[/tex]

So, it will take 10 s to reach the ground.

A projectile is launched horizontally at a speed of 40 meters per second from a platform located a vertical distance h above the ground. The projectile strikes the ground after time at horizontal distance from the base of the platform. [Neglect friction.]

Calculate the vertical distance, h, if the projectile's total time of flight is 4.5 seconds. You must show work to earn full credit with the minimum 3 steps:
1. Equation used
2. Substitution with correct units
3. Final answer with correct units

Answers

Answer:1

Explanation:t=rad2h/g

The launch of projectiles allows to find the height of the body launched horizontally is:

The height is 99.2 m

Projectile launching is an application of kinematics where there is no acceleration on the x-axis and the y-axis is the gravity acceleration.

In the attachment we see a diagram of the movement, as the body is thrown horizontally, its initial vertical speed is zero.

           y = y₀ + [tex]v_o_y[/tex] t - ½ g t²

Where y, y₀i are the current and initial heights, respectively, [tex]v_{oy}[/tex] the vertical initial velocity, g the acceleration of gravity and t the time.

           0 =y₀ + 0 - ½ g t²

           y₀ = ½ g t²

let's calculate

           y₀ = ½ 9.8 4.5²

           y₀ = 99.2 m

          y₀ = h = 99.2 m

This is the initial height of the object when it is thrown.

In conclusion using the projectile launch we can find the height of the horizontally launched body is:

The height is 99.2 m

Learn more here:  brainly.com/question/10903823

Which of the statements are true about the collision of two objects with different
masses based on Newton's laws of motion?
A. Each object experiences an equal and opposite force.
B. The more massive object will exert a greater force on the less massive object.
Each object will accelerate in an opposite direction from the other but at a
different rate.
D. The less massive object will accelerate due to the force of the collision, but the
more massive object will not.​

Answers

Answer:

A. TRUE

B. TRUE

C. It depends on the mass of both the objects

D. TRUE

How does a jack spread out the work over a large distance?

Answers

Each complete rotation of a jack handle applies a small force over a large distance. A small force exerted over a large distance becomes a large force exerted over a short distance. Each rotation lifts the car only a very short distance.

In consideration of the above diagram, a projectile is launched at 45 with an initial horizontal velocity (V0x) of 3 m/s. Calculate the Vox which is the actual launch velocity at 45 in m/s.

Answers

CFISD too huh? :D

also tryna get the answer

An 85kg mass accelerates at 5.5m/s2 what force was applied

Answers

Answer:

467.5 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 85 × 5.5

We have the final answer as

467.5 N

Hope this helps you

calculate the velocity of an object moved around a circle with a radius of 1.65m and an acceleration of 3.5 m/s^2​

Answers

Answer:

2.4m/s

Explanation:

What is the modern periodic table of elements?

A. A chart organizing all elements by their atomic mass

B. A list of all elements occuring in nature

C. A chart organizing all elements by their atomic number

D. A list of all elements created by humans

Answers

C is the correct answer
I agreee ^ with that person

if 56 j of work energy is required to lift a dumbbell to a height of 7m, what is the weight of the dumbbell?​

Answers

Answer:

8 N

Explanation:

work=force*distance

force=work/distance

=56/7

=8

calculate the height from from which a body is released from rest if its velocity just before hitting the ground is30m\s

Answers

Answer:

height = 45 m

Explanation:

Initial velocity = 0 m/s

Final velocity = 30 m/s

Acceleration due to gravity = +10m/s^2 ( because ball is going down )

Using the eqn of motion

[tex] {v}^{2} - {u}^{2} = 2gh[/tex]

where v= final velocity ; u = initial velocity ; g = acceleration due to gravity ; h = height

So,

[tex] {30}^{2} - {0}^{2} = 2 \times 10 \times h[/tex]

[tex] = > 20h = 900[/tex]

[tex] = > h = \frac{900}{20} = 45[/tex]

compare the 3 different types of waves

Answers

Answer:Mechanical waves, electromagnetic waves, and matter waves.

Explanation: does are the waves

How many seconds are there in a calendar year,given that a calendar year has 365.24 days in it?

Answers

Answer:

31556736

Explanation:

Since there are 60 seconds in a minute, 60 minutes in an hour, 24 hours in a day, and 365.24 days in a year, then you multiply all of those.

60*60*24*365.24 =

31556736

answer = 31.6 million seconds

earth yr - 365.24 days / 8,765 hours / 526,000 minutes / 31.6 million seconds

Man has never directly reached the inner layers of the Earth. But what phenomena allow to determine its chemical composition?
A)Surface wave propagation.
B)Plate displacement
C)Emanation of lava in volcanoes
D)Changes in the Earth's landscape
E)Waves formed in tidal waves

Answers

I think letter A.Surface wave propagation

Which two factors affect the amount of force seen in objects?

Answers

Answer:thanks

Explanation:xixo

gv

ASAP it’s timed!!
An object has a mass of 5 kg. What force is needed to accelerate it at 6 m/s? (Formula: Fema)
0.89 N
1.2 N
11 N
30 N

Answers

Answer:

30N is the correct answer

30 N is the answer
Step by step: 30N

What is the acceleration of an object with a mass of 367 kg when a net force of 183 N is applied to it

Answers

Answer:

[tex]0.5m/s^{2}[/tex]

Explanation:

F= m x a

a= [tex]\frac{F}{m}[/tex] =  [tex]\frac{183 N}{367 kg}[/tex]  = [tex]\frac{0.4986 N}{kg}[/tex] = [tex]\frac{0.4986 kg*m/s^{2} }{kg}[/tex] = [tex]0.5 m/s^{2}[/tex]

Hopefully, this is right!

A transformer has 1000 turns on the primary coil.
The voltage applied to the primary coil is 230V a.c,
How many turns are on the secondary coil if the output
voltage is 46 V a.c.?
A)20 B)200 C)2000 D4000 E)8000

Answers

Answer:

200

Explanation:

Given parameters:

Number of turns in primary coil  = 1000 turns

Primary voltage  = 230V

Secondary voltage  = 46V

Unknown:

Number of turns in secondary coil = ?

Solution:

To solve this problem, we have to use the expression for solving problems related with transformers;

   

        [tex]\frac{Vs}{Ns}[/tex]   = [tex]\frac{Vp}{Np}[/tex]  

Vs is the secondary voltage

Ns is the number of secondary turns

Vp is the primary voltage

Np is the number of primary turns

 Now insert the parameters and solve;

         [tex]\frac{46}{Ns}[/tex]   = [tex]\frac{230}{1000}[/tex]

          46 x 1000 = 230Ns

             Ns = 200

What are indicative acts? FORENSICS

Answers

Answer:

Actions or behaviors that may have taken place before death.

Do you wanna know how I know? No.... You do not wanna know how I know that you know what I known that you know I know

Explanation:

You Know?

amp, is named after a person who was the person

Answers

Answer:

Explanation:

Named for 19th-century French physicist André-Marie Ampère, it represents a flow of one coulomb of electricity per second.

what is marketing according to AMA​

Answers

Answer:

The new 2007 AMA defini- tion is as follows: Marketing is the activity, set of institutions, and processes for creating, communicating, delivering, and exchanging offerings that have value for customers, clients, partners, and society at large.

Explanation:

The graph shows the speeds of two bicyclists on their way to school. what is the speed of bicycle B

Answers

Answer: 0.3

Explanation: Jusy took it and got a 100

Answer: 0.3

Explanation: This is right trust me I answered this and it was correct!!

The gradual temperature change from one season to the next is due to what? view attachment

Answers

Global warming jk part of the earth is either facing the sun or part of the sun or away from the sun

What is also known as watered carbons

Answers

The name carbohydrate means "watered carbon" or carbon with attached water molecules. Many carbohydrates have empirical formuli which would imply about equal numbers of carbon and water molecules. For example, the glucose formula C6H12O6 suggests six carbon atoms and six water molecules.

Answer:

The name carbohydrate means "watered carbon" or carbon with attached water molecules. Many carbohydrates have empirical formuli which would imply about equal numbers of carbon and water molecules. For example, the glucose formula C6H12O6 suggests six carbon atoms and six water molecules.

A car enters the freeway with a speed of 6.4 m/s and accelerates uniformly for 3.2 km in 3.5 min. How FAST (m/s) is the car moving after this time?

Answers

here i found this on socratic hope this helps

A car turns from a road into a parking lot and into an available parking space. The car's initial velocity is 4 m/s [E 45° N]. The car's velocity just before the driver decreases speed is 4 m/s [E 10° N]. The turn takes 3s. What's the average acceleration of the car during the turn? The answer should have directions with an angle.

Answers

Answer:

Explanation:

From the given information:

The car's initial velocity = 4 m/s in the direction of east 45° due north

We can therefore express the vector of this component form as:

v₁ = (4 m/s) (cos(45º)i + sin(45º)j)

v₁ = (2.83 m/s)i + (2.83 m/s)j

Similarly, the car's final velocity = 4 m/s in the direction of the east side 10º north

v₂ = (4 m/s) (cos(10º) i + sin(10º) j)

v₂ = (3.94 m/s) i + (0.695 m/s) j

From the first equation of motion

v = u + at

Making acceleration "a" the subject of the formula, we have:

a = (v - u )/t

a = (v₂ - v₁)/t

a =  (0.370 m/s²) + (-0.711 m/s²)

The magnitude of the avg. acceleration is:

[tex]|| a||= \sqrt{(0.370 m/s^2)^2 + (-0.711 m/s^2)^2)[/tex]

[tex]|| a||= 0.8015 \ m/s^2[/tex]

And;

The direction can be determined by taking the tangent of the acceleration:

i.e.

[tex]tan(\theta) = \dfrac{-0.711 m/s^2}{ 0.370 m/s^2}[/tex]

[tex]tan(\theta) = -1.9216[/tex]

[tex]\theta = tan^{-1} ( -1.9216 )[/tex]

[tex]\mathbf{\theta = -62.51 ^0}[/tex]

Thus, the direction of the angle is approximately  S 62.51º E

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